BSG Einheit Pankow vs Lok Stendal analysis
Possible results
Probability of each exact result
Probability of each margin of victory
55.9%
Win probability
2.25
Expected goals
9-0
<0%
+9
<0%
8-0
<0%
9-1
<0%
+8
0.1%
7-0
0.1%
8-1
0.1%
9-2
<0%
+7
0.2%
6-0
0.5%
7-1
0.2%
8-2
<0%
+6
0.7%
5-0
1.2%
6-1
0.6%
7-2
0.2%
8-3
<0%
+5
2%
4-0
2.7%
5-1
1.7%
6-2
0.5%
7-3
0.1%
+4
4.9%
3-0
4.7%
4-1
3.8%
5-2
1.2%
6-3
0.2%
7-4
<0%
+3
10.1%
2-0
6.3%
3-1
6.8%
4-2
2.8%
5-3
0.6%
6-4
0.1%
+2
16.6%
1-0
5.6%
2-1
9.1%
3-2
4.9%
4-3
1.3%
5-4
0.2%
6-5
<0%
+1
21.2%
20%
Draw
0-0
2.5%
1-1
8.1%
2-2
6.6%
3-3
2.4%
4-4
0.5%
5-5
0.1%
0
20%
24.1%
Win probability
1.44
Expected goals
0-1
3.6%
1-2
5.8%
2-3
3.1%
3-4
0.8%
4-5
0.1%
5-6
0%
-1
13.6%
0-2
2.6%
1-3
2.8%
2-4
1.1%
3-5
0.2%
4-6
0%
-2
6.8%
0-3
1.2%
1-4
1%
2-5
0.3%
3-6
0.1%
-3
2.6%
0-4
0.4%
1-5
0.3%
2-6
0.1%
3-7
0%
-4
0.8%
0-5
0.1%
1-6
0.1%
2-7
0%
-5
0.2%
0-6
0%
1-7
0%
-6
<0%
ELO Graph/Inclination
← Defensive
Tilt
Attacking →
ELO progression
Next opponents in ELO points
Matches
BSG Einheit Pankow
|
1%
X%
2%
|
ELO | ELO Cont. | ▵ELO | ±ELO | |
|---|---|---|---|---|---|
| 03 Sep. 1950 |
HAL
8 - 1
BEP
69%
16%
15%
|
74 | 80 | 6 | 0 |
Matches
Lok Stendal
|
1%
X%
2%
|
ELO | ELO Cont. | ▵ELO | ±ELO | |
|---|---|---|---|---|---|
| 03 Sep. 1950 |
LAS
0 - 2
SGD
64%
18%
18%
|
76 | 72 | 4 | 0 |
| 16 Apr. 1950 |
LAS
5 - 1
ANK
77%
13%
10%
|
74 | 61 | 13 | +2 |
| 09 Apr. 1950 |
LAS
3 - 0
ERF
30%
22%
48%
|
73 | 82 | 9 | +1 |
| 02 Apr. 1950 |
BAB
3 - 1
LAS
51%
21%
29%
|
74 | 68 | 6 | -1 |
| 19 Mar. 1950 |
FMS
0 - 2
LAS
35%
22%
43%
|
73 | 59 | 14 | +1 |